Click here??to get an answer to your question ? If O is any point inside a rectangle ABCD . Prove that OB^2 + OD^2 = OA^2 + OC^2 .
5/29/2018 · Prove that OB2 + OD2 = OA2 + OC2. Given : Rectangle ABCD , and a point O inside rectangle . To prove :- OB2 + OD2 = OA2 + OC2 Proof :- Let us draw a line PQ, through O which is parallel to BC. Hence, PQ II BC ? PQ II AD All angles of a rectangle are 90° , So, ? A = ? B = ? C = ? D = 90° Since, PQ II BC & AB is the transversal ? APO = ? B ? APO = …
Answer. Through O , draw P Q ? BC so that P lies on AB andQ lies on DC. Now, P Q ? BC. Therefore, P Q? AB andP Q ? DC [?B = 90? and?C = 90?. So, ?BP Q= 90? and?C QP = 90?. Therefore, BP QC and AP QD are both rectangles . Now, from ?OP B, OB2 = BP 2 +OP 2…(i), 5/9/2020 · Please add description.
8/16/2020 · Secondary School. answer. answered. O is any point inside a rectangle ABCD as shown in the figure. Prove that OB2 + OD2 = OA2 + OC2. 2. See answers. report flag outlined. bell outlined.
O is Any Point Inside a Rectangle Abcd. Prove That: Ob2 + Od2 = Oc2 + Oa2. – Mathematics, 1/29/2019 · O is any point inside a rectangle ABCD (see Fig. 6.52). Prove that OB2 + OD2 = OA2 + OC2.
Let O be any point inside the rectangle . Draw lines through O parallel to AB and BC. Let P and R be the feet of the perpendicular from O on AB and DC, respectively. Let Q and S be the feet of the perpendicular from O on BC and AD, respectively. Let BP = CR = y and AP = DR = L-y. Let BQ =AS = x and QC = SD = W-x.
7/26/2012 · If O is any point inside a rectangle ABCD , then prove that OA2 + OC2 = OB2 + OD2 – Maths – Triangles, Triangles, Class 10, O is any point inside arectangle ABCD . Prove thatOB2 + OD2= OC2 + OA2Most Important Question from Triangles for Board ExamMaths Class 1…
